
Tobias Weltner - Hey, Scripting GuyBlog talks Regex A recorded presentation of Tome Tanasovskis regex talk for the UK PowerShell UserGroup. Text and Regular Expressions - Master-PowerShell With Dr. $txt = $txt -replace (" whitespacebetweennames","\.

Param($txt, $lastnameFirstname, $firstnameLastname) and then replace the comma with a semicolon. here i need to replace the whitespace between the firstname and lastname with a period.

"Īnother format that often is given is "firstname lastname, firstname lastname." so it will result in "lastname, firstname lastname, firstname. what needs to happen here is i need to replace every second comma with a semicolon. Besides the Replace() method, we also have the -replace operator. One format that is often given is "lastname, firstname, lastname, firstname. This is being used for adding multiple users to group mailboxes, dist lists, security group memberhips, etc. THis string is a list of users, which may be given in several different formats, and then modify that string to a standard that Active directory will recognize. The reason that it doesn't work, is because it first passes $1 (the string, not the value of $1) to the function, executes it and only then does it do the replace.I am writing a script that modifies a given string to an applicable string. ::ToBase64String((get-content $path -encoding byte)) I was hoping the following would work, but it doesn't: function Get-Base64($path) When I use YYYY-MM-DD-HH-SS I make sure the invoice I’m writing always has the highest number. Now, I want to include the base64 encoded image. $text = $text -replace "-(\d*)-", 'This is the image: $1' NET method ().replace does not support regex. Be aware, that you need to use the -replace statement to bring RegEx in action. It will remove all digits from the string. NET or Perl, the difficulty in using PowerShell is not. Removing all Digits with the \d+ Statement (RegEx) \d+ is a regex statement (Regular expressions).

For someone familiar with regular expressions, especially as they are implemented in. NET in turn essentially uses Perl 5’s regular expression syntax, with a few added features such as named captures.

However, the replacement string is not hardcoded, it's calculated from a function: $text = "the image is -12345-" In regular expressions, as in much else, PowerShell uses the. I'm trying to replace part of a string in Powershell.
